Answer to Question #335811 in Chemistry for shimmy

Question

1. A balloon contains 14.0 L of air at a pressure of 760 torr. What will the volume of the air be when the balloon is taken to a depth of 10 ft in a swimming pool where the pressure is 981 torr? The temperature of the air does not change.

Answer 1

Given:

P₁ = 760 torr

V₁ = 14.0 L

T₁ = T₂ = constant

P₂ = 981 torr

V₂ = unknown

Formula: P₁V₁ = P₂V₂

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the volume of the air, solve the equation for V₂:

V₂ = P₁V₁ / P₂

V₂ = (760 torr × 14.0 L) / (981 torr) = 10.846 L = 10.8 L

V₂ = 10.8 L

Answer: The volume of the air will be 10.8 liters