Answer to Question #335811 in Chemistry for shimmy

Question #335811

1. A balloon contains 14.0 L of air at a pressure of 760 torr. What will the volume of the air be when the balloon is taken to a depth of 10 ft in a swimming pool where the pressure is 981 torr? The temperature of the air does not change.



1
Expert's answer
2022-05-03T03:45:05-0400

Given:

P1 = 760 torr

V1 = 14.0 L

T1 = T2 = constant

P2 = 981 torr

V2 = unknown


Formula: P1V1 = P2V2


Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P1V1 = P2V2

To find the volume of the air, solve the equation for V2:

V2 = P1V1 / P2

V2 = (760 torr × 14.0 L) / (981 torr) = 10.846 L = 10.8 L

V2 = 10.8 L


Answer: The volume of the air will be 10.8 liters

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS