1. If 15.0 L Neon at 60 0C is heated at constant pressure, what temperature will it have if it occupies a volume of 4.50 L?
Given:
V1 = 15.0 L
T1 = 60°C + 273.15 = 333.15 K
P1 = P2 = constant
V2 = 4.50 L
T2 = ???
Solution:
Since the pressure and amount of gas remain unchanged, Charles's law can be used.
Charles's law can be expressed as: V1 / T1 = V2 / T2
V1T2 = V2T1
To find the temperture, solve the equation for T2:
T2 = V2T1 / V1
T2 = (4.50 L × 333.15 K) / (15.0 L) = 99.945 K = 100 K
T2 = 100 K or −173°C
Answer: at 100 K
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