Answer to Question #312640 in Chemistry for grey tyrant

Question

3. Lead(II) sulfate formed in the reaction of 145 mL of 0.123 M lead(II) nitrate and excess sodium sulfate.

a. Write the balance chemical equation

b. What type of chemical reaction?

Answer 1

Solution:

lead(II) nitrate = Pb(NO₃)₂

sodium sulfate = Na₂SO₄

lead(II) sulfate = PbSO₄

(a): Balanced chemical equation:

Pb(NO₃)₂(aq) + Na₂SO₄(aq) ⟶ PbSO₄(s) + 2NaNO₃(aq)

(b): Double Displacement Reaction