Answer to Question #312633 in Chemistry for izel

Question

the volume of a certain quantity of n2 gas at 20 Celsius and 100.0 kPa is 15.0L. What will be its volume at 27 Celsius at 1.5 atm?

Answer 1

P₁ = 100.0 kPa × (1 atm / 101.325 kPa) = 0.987 atm

V₁ = 15.0 L

T₁ = 20°C + 273.15 = 293.15 K

P₂ = 1.5 atm

V₂ = unknown

T₂ = 27°C + 273.15 = 300.15

Solution:

Combined Gas Law can be used:

P₁V₁/T₁ = P₂V₂/T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (0.987 atm × 15.0 L × 300.15 K) / (1.5 atm × 293.15 K) = 10.1 L

V₂ = 10.1 L

Answer: The volume will be 10.1 liters