Answer to Question #305327 in Chemistry for Ray

Question

A sample of 0.846 mol Ne gas at 18°C has a volume of 18.5 L under a pressure of 1.09 atm. The gas is then compressed to 10.5 L at 18°C. Calculate the final pressure.

Answer 1

P₁ = 1.09 atm

V₁ = 18.5 L

n₁ = n₂ = 0.846 mol Ne gas = const

T₁ = T₂ = 18°C = const

P₂ = unknown

V₂ = 10.5 L

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the final pressure, solve the equation for P₂:

P₂ = P₁V₁ / V₂

P₂ = (1.09 atm × 18.5 L) / (10.5 L) = 1.92 atm

P₂ = 1.92 atm

 

Answer: The final pressure of Ne gas is 1.92 atm