Calculate the mass of carbon in 10.00 g of glucose (C6H1206). Show the step by step process.
Solution:
1) Calculate the molar mass of glucose (C6H1206):
M(C6H1206) = 6×Ar(C) + 12×Ar(H) + 6×Ar(O)
M(C6H1206) = 6×12.011 + 12×1.008 + 6×15.999 = 180.156 (g/mol)
M(C6H1206) = 180.156 g/mol
2) Calculate the mass percent of carbon (C) in glucose (C6H1206):
Mass percent of C = [6×Ar(C) / M(C6H1206)] × 100%
Mass percent of C = (6×12.011 / 180.156) × 100% = 40.00%
3) Calculate the the mass of carbon (C) in glucose (C6H1206):
Mass of C = (Mass percent of C × Mass of glucose) / 100%
Mass of C = (40.00% × 10.00 g) / 100% = 4 g
Mass of C = 4 g
Answer: The mass of carbon (C) is 4 grams
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