Answer to Question #298069 in Chemistry for Dave

Question

How many Na+ ions are contained in 4.62g Na3PO4?

Answer 1

Solution:

The molar mass of Na₃PO₄ is 163.94 g/mol

Therefore,

Moles of Na₃PO₄ = (4.62 g Na₃PO₄) × (1 mol Na₃PO₄ / 163.94 g Na₃PO₄) = 0.02818 mol Na₃PO₄

Na₃PO₄ → 3Na⁺ + PO₄^3-

Therefore,

1 mol of Na₃PO₄ contains 3 mol of Na⁺ ions

Thus, 0.02818 mol of Na₃PO₄ contains:

(0.02818 mol Na₃PO₄) × (3 mol Na⁺ ions / 1 mol Na₃PO₄) = 0.08454 mol Na⁺ ions

One mole of any substance contains 6.022×10²³ particles.

Therefore,

Number of Na⁺ ions = (0.08454 mol) × (6.022×10²³ ions / 1 mol) = 5.09×10²² ions

Answer: 5.09×10²² of Na⁺ ions