Question

Consider a solution prepared by adding 2.70 grams acetic acid to 122.8 grams of water:

a. what is the percentage by mass of concentration of acetic acid in this solution?

b. what is the mass of acetic acid is present in 25.0 grams of this solution?

Answer 1

a) % = (100 x m_solute) / (m_solvent + m_solute)

% = (100 x 2.70) / (2.70 + 122.8) = 2.1%

b) 25.0 grams of this solution contains 25.0 x 0.021 = 0.5 g of acetic acid