Hi, i have this reaction: 4 NH3 + 3 O2 → 2 N2 + 6 H2O and I only know the moles of NH3 that are: 0.014502748.
how do i get all the others?
4 NH3 + 3 O2 → 2 N2 + 6 H2O
According to the equation:
n (O2) = 3/4 x n(NH3) = 3/4 x 0.014502748 = 0.01087706 mol
n (N2) = 2/4 x n(NH3) = 2/4 x 0.014502748 = 0.00725137 mol
n (H2O) = 6/4 x n(NH3) = 6/4 x 0.014502748 = 0.02175411 mol
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