Answer to Question #213680 in Chemistry for anuj

Question

Sulfuryl chloride is an inorganic compound with the formula SO2Cl2. It is a colourless liquid with a pungent odour. A quantity of 5.75 g of SO2Cl2 was placed in a 3.00 L flask. At 375 °C, there is 0.035 mole of Cl2 present. SO2Cl2(g) SO2(g) + Cl2(g) .calculate kc and kp

Answer 1

given wt. of SO₂Cl₂ = 5.75 g

Molecular wt. of SO₂Cl₂ = 134.9698

Moles of $SO_2Cl_2 =\frac {5.75}{134.9698}=0.043moles$

Kc​ = 1.639