Answer to Question #206031 in Chemistry for marianna

Question

You have 1.00 mol/L solution of sulfuric acid. Describe how you would use this solution to make 250.0 mL of a 0.500 mol/L solution of sulfuric acid. *Hint: Your answer should include more than just a calculation

Answer 1

n₁ = n₂

C_M = n / V

n = C_M x V

C_M1 x V₁ = C_M2 x V₂

1.00 x V₁ = 0.500 x 0.2500

V₁ = (0.500 x 0.2500) / 1.00 = 0.125 L

0.125 L of 1.00 mol/L solution of sulfuric acid is required to prepare 250.0 mL of a 0.500 mol/L solution of sulfuric acid.