Answer to Question #205602 in Chemistry for marianna

Question

 What volume of a 1.60 mol/L stock solution of calcium chloride would you use to make a 530 mL of a 0.34 mol/L solution?

Answer 1

C₁ = 1.60 mol/L

V₁ = unknown

C₂ = 0.34 mol/L

V₂ = 530 mL

Solution:

The equation for dilution calculations can be used.

where:

c₁, V₁ - the molarity and volume of the concentrated solution (stock solution)

c₂, V₂ - the molarity and volume of the diluted solution

Thus:

(1.60 mol/L) × V₁ = (0.34 mol/L) × (530 mL)

V₁ = (0.34 mol/L × 530 mL) / (1.60 mol/L) = 112.625 mL = 112.6 mL

V₁ = 112.6 mL

Answer: 112.6 mL