Answer to Question #179184 in Chemistry for Alexandra Tulk

Question

154 mL of 3.87 mol/L barium hydroxide is needed to fully react with 146 mL of lithium sulfate solution what is the molar concentration of lithium sulfate solution

Answer 1

Solution:

Balanced chemical equation:

Ba(OH)₂ + Li₂SO₄ → BaSO₄ + 2LiOH

According to the equation above: n(Ba(OH)₂) = n(Li₂SO₄)

C(Ba(OH)₂) × V(Ba(OH)₂) = C(Li₂SO₄) × V(Li₂SO₄)

Divide to isolate C(Li₂SO₄):

C(Li₂SO₄) = C(Ba(OH)₂) × V(Ba(OH)₂) / V(Li₂SO₄)

Plug in the numbers and solve for C(Li₂SO₄):

C(Li₂SO₄) = (3.87 mol/L × 154 mL) / (146 mL) = 4.08 mol/L

C(Li₂SO₄) = 4.08 mol/L

Answer: The molar concentration of lithium sulfate (Li₂SO₄) solution is 4.08 mol/L.