Calculate the amount of Calcium chloride dihydrate in grams needed to make a 250 mL solution with a final Normality of 2,000 meq/L
Cn = n/V
n = m/e
e = M/valency factor
M (Ca(OH)2) = 74.1 g/mol
e (Ca(OH)2) = 74.1/2 = 37.05
2,000 meq/L = 2 eq/L
n (Ca(OH)2) = Cn x V = 2 x 0.25 = 0.5 n
m (Ca(OH)2) = n x e = 0.5 x 37.05 = 18.5 g
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