Lesson 12. Questions 1 to 5—convert the following number of moles to number of particles:
Solution:
One mole of any substance contains 6.022×1023 particles.
Hence,
(1) 2.0 moles of CaCl2:
Number of CaCl2 molecules = (2.0 mol) × (6.022×1023 molecules / 1 mol) = 1.20×1024 CaCl2 molecules
Number of CaCl2 molecules = 1.20×1024 molecules
(2) 1.5 moles of copper(II) ions:
Number of copper(II) ions = (1.5 mol) × (6.022×1023 ions / 1 mol) = 9.03×1023 Cu2+ ions
Number of copper(II) ions = 9.03×1023 ions
(3) 0.01 moles of H2O:
Number of H2O molecules = (0.01 mol) × (6.022×1023 molecules / 1 mol) = 6.02×1021 H2O molecules
Number of H2O molecules = 6.02×1021 molecules
(4) 5.0 moles of gold atoms:
Number of gold atoms = (5.0 mol) × (6.022×1023 atoms / 1 mol) = 3.01×1024 Au atoms
Number of gold atoms = 3.01×1024 atoms
(5) 0.0025 moles of HCl:
Number of HCl molecules = (0.0025 mol) × (6.022×1023 molecules / 1 mol) = 1.506×1021 HCl molecules
Number of HCl molecules = 1.51×1021 molecules
(6) What is the mass of 1 mole of Mg atoms?
One mole of magnesium (Mg) atoms has a mass of 24.31 g.
(7) What is the molar mass of aluminum?
The molar mass of aluminum (Al) is 26.982 g/mol.
(8) What is the mass of 1 mole of oxygen atoms?
One mole of oxygen (O) atoms has a mass of 16 g.
(9) What is the mass of 1 mole of oxygen molecules, O2?
One mole of oxygen molecules (O2) has a mass of 32 g.
(10) Calculate the molar mass of NaOH.
M(Na) = 22.989 g/mol
M(O) = 15.999 g/mol
M(H) =1.0079 g/mol
So, its molar mass is 22.989 + 15.999 + 1.0079 = 39.996 g/mol
M(NaOH) = 39.996 g/mol
(11) What is the mass of 1.0 mole of CaCl2?
The molar mass of CaCl2 is 110.98 g/mol.
So, 1.0 mole of CaCl2 has a mass of 110.98 g.
(12) Calculate the molar mass of Cu(NO3)2.
M(Cu) = 63.546 g/mol
M(N) = 14.0067 g/mol
M(O) = 15.999 g/mol
So, its molar mass is 63.546 + 2×14.0067 + 6×15.999 = 187.5534 g/mol = 187.55 g/mol
M(Cu(NO3)2) = 187.55 g/mol
(13) Calculate the molar mass of Al2(SO4)3.
M(Al) = 26.98154 g/mol
M(S) = 32.065 g/mol
M(O) = 15.999 g/mol
So, its molar mass is 2×26.98154 + 3×32.065 + 12×15.999 = 342.146 g/mol = 342.15 g/mol
M(Al2(SO4)3) = 342.15 g/mol
Comments
Leave a comment