Question

2 FeCl2 + Cl2 → 2 FeCl3
If 3.7 x 10^25 particles of Cl2 are reacted, how many grams of FeCl2 will also be reacted?

Answer 1

1 mole contains 6.02214076 × 10²³ particles.

3.7 x 10²⁵ particles of Cl₂ is equal to: 3.7 x 10²⁵ / 6.02214076 × 10²³ = 61.4 moles

According to the equation, 1 mole of Cl₂ requires moles of FeCl₂.

n = m/M

m = n x M

M (FeCl₂) = 126.751 g/mol

m (FeCl₂) = 61.4 x 126.751 = 7 788 g