Answer to Question #170406 in Chemistry for Ava Brooke

Question

How much titanium in grams is required to release 538.13 kJ of heat?

Ti + 2 B -> TiB₂  

△ H

 = 316 kJ/mol

Answer 1

Solution:

The balanced thermochemical equation:

Ti + 2B → TiB₂, △H = 316 kJ/mol

 

The equivalences for this thermochemical equation are:

1 mol Ti ⇔ 2 mol B ⇔ 1 mol TiB₂ ⇔ 316 kJ/mol

 

Determine the moles of titanium (Ti) using the thermochemical equation:

538.13 kJ × (1 mol Ti / 316 kJ/mol) = 1.703 mol Ti

 

Mass of Ti = Moles of Ti × Molar mass of Ti

Molar mass of Ti is 47.867 g mol^-1.

Hence,

Mass of Ti = 1.703 mol × 47.867 g mol^-1 = 81.5148 g = 81.5 g

Mass of Ti = 81.5 g

Answer: 81.5 grams of titanium (Ti) is required.