What is the molecular formula if the empirical formula is CH2 and the original formula mass is 210.39?
The empirical formula can be calculated as following:
(molar mass of empirical form) x = molar mass of compound
(Mr[C] + 2 × Mr[H]) x = Mr[compound]
(12 g/mol + 2 × 1 g/mol) x = 210.39 g/mol
14 x = 210.39
x = 15
From here, the empirical formula is (CH2)15 = C15H30
Answer: C15H30
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