In the electrolysis of melted MgCl2, an electric current of 52115 Coulomb is used, the mass of Mg produced is ...
Solution:
Electrolysis of the molten MgCl2:
Mg2+ + 2e- → Mg (at the (-)cathode).
2Cl- - 2e- → Cl2 (at the (+)anode).
The overall reaction is:
MgCl2(l) → Mg(s) + Cl2(g)
By Faraday's first law
w = z × Q
where:
z = Electrochemical equivalent = Atomic mass / (Electrons × 96500)
Q = Coulombs of electricity
Hence,
Mass of Mg = (M × Q) / (ne × F)
Mass of Mg = (24 × 52115) / (2 × 96500) = 6.48 g
Mass of Mg = 6.48 g
Answer: 6.48 grams of Mg is produced.
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