A 350g sample of an unknown solid is heated continuously from 10°C to 75°C. Scientists determine that the energy change during that process is 4,860J. If the solid does not change phase during the heating process, what must its specific heat capacity be?
Solution:
q = m × C × ΔT
q = m × C × (Tf - Ti),
where:
q = amount of heat energy gained or lost by substance
m = mass of sample
C = specific heat capacity (J oC-1 g-1)
Tf = final temperature
Ti = initial temperature
Thus:
4860 J = (350 g) × C × (75 - 10)oC
4860 J = C × 22750 oC g
C = 0.213 J oC-1 g-1
Answer: The specific heat capacity of an unknown solid is 0.213 J oC-1 g-1.
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