Answer to Question #161426 in Chemistry for Alex

Question

How many moles of aluminum chloride are produced when 92.30 g of aluminum chlorate is heated in a decomposition reaction? 

Answer 1

The decomposition of aluminum chlorate can be shown as follows:

Al(ClO₃)₃ = AlCl₃ + O₂

From here:

m (AlCl₃) = m (Al(ClO₃)₃) × Mr(AlCl₃) / Mr(Al(ClO₃)₃) = 92.30 g × 133.34 g/mol / 277.33 g/mol = 44.38 g

Answer: 44.38 g