3NO2 + 1H2O --> 2HNO3
How many moles of water are needed to react with 8.4 moles of NO2?
Solution:
The balanced chemical equation:
3NO2 + H2O → 2HNO3 + NO
According to the chemical equation above: n(NO2)/3 = n(H2O)
Hence,
n(H2O) = n(NO2) / 3 = 8.4 mol / 3 = 2.8 mol
n(H2O) = 2.8 mol
Answer: 2.8 moles of water (H2O) are needed to react with 8.4 moles of NO2
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