Answer to Question #158759 in Chemistry for lizeth

Question

1. 12 HClO4 + P4O10 -> 4H3PO4 + 6 Cl2O7

given 5.48 mol HClO4, how many miles of H3PO4 could be produced (assuming abundant P4O10 is present)

1. 8 CO + 17 H2 -> C8H18 + 8 H2O

assuming an unlimited supply of hydrogen gas (H2), how many miles of C8H18 could be produced with 26.79 miles of carbon monoxide?

1. B2Br6 + 6HNO3 -> 2 B(NO3)3 + 6 HBr

given 276.2 g B2Br6, how many grams of HBr could be produced? assume you have more than enough HNO3

Answer 1

Solution:

(1):

The balanced chemical equation:

12HClO₄ + P₄O₁₀ → 4H₃PO₄ + 6Cl₂O₇

According to the chemical equation:

n(HClO₄)/12 = n(H₃PO₄)/4

n(HClO₄)/3 = n(H₃PO₄)

Hence,

n(H₃PO₄) = n(HClO₄) / 3 = 5.48 mol / 3 = 1.82667 mol = 1.83 mol

n(H₃PO₄) = 1.83 mol

Answer (1): 1.83 moles of H₃PO₄ could be produced.

(2):

The balanced chemical equation:

8CO + 17H₂ → C₈H₁₈ + 8H₂O

According to the chemical equation:

n(CO)/8 = n(C₈H₁₈)

Hence,

n(C₈H₁₈) = n(CO) / 8 = 26.79 mol / 8 = 3.34875 mol = 3.35 mol

n(C₈H₁₈) = 3.35 mol

Answer (2): 3.35 moles of C₈H₁₈ could be produced.

(3):

The balanced chemical equation:

B₂Br₆ + 6HNO₃ → 2B(NO₃)₃ + 6HBr

According to the chemical equation: n(B₂Br₆) = n(HBr)/6

or:

6 × m(B₂Br₆) / M(B₂Br₆) = m(HBr) / M(HBr)

The molar mass of B₂Br₆ is 501.046 g mol^-1.

The molar mass of HBr is 80.912 g mol^-1.

Hence,

m(HBr) = 6 × m(B₂Br₆) × M(HBr) / M(B₂Br₆)

m(HBr) = (6 × 276.2 g × 80.912 g mol^-1) / (501.046 g mol^-1) = 267.6 g

m(HBr) = 267.6 g

Answer (3): 267.6 grams of HBr could be produced.