Answer to Question #149481 in Chemistry for Sally saade

Question

How many grams of NO are needed to produce 20g of NO2?

Answer 1

Solution:

Nitric oxide (NO) reacts with oxygen gas (O₂) to form nitrogen dioxide (NO₂):

2NO(g) + O₂(g) → 2NO₂(g)

According to the equation: n(NO) = n(NO₂)

Moles of NO₂ = n(NO₂) = Mass of NO₂ / Molar mass of NO₂

The molar mass of NO₂ is 46 g/mol.

Hence,

n(NO₂) = 20 g / 46 g mol^-1 = 0.4348 mol

n(NO) = n(NO₂) = 0.4348 mol

Moles of NO = n(NO) = Mass of NO / Molar mass of NO

The molar mass of NO is 30 g/mol.

Hence,

Mass of NO = Moles of NO × Molar mass of NO

Mass of NO = 0.4348 mol × 30 g/mol = 13.044 g

Mass of NO is 13.044 grams

Answer: 13.044 grams of NO are needed to produce 20g of NO₂.

(20 g NO₂) × (1 mol NO₂ / 46 g NO₂) × (30 g NO / 1 mol NO) = 13.043 g NO