Answer to Question #149463 in Chemistry for Hammad Ali

Question

How many nitrogen atoms are present in 2.79 mol of NH3

Answer 1

Solution:

1 mole of NH₃ has 1 mole of N atoms and 3 moles of H atoms.

So, 2.79 mol NH₃ have 2.79 mol of N atoms.

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

nitrogen atoms = (2.79 mol of N atoms) × (6.022×10²³ atoms / 1 mol) = 16.80×10²³ atoms of N

nitrogen atoms = 16.80×10²³ atoms or 1.68×10²⁴ atoms

Answer: 1.68×10²⁴ atoms of nitrogen are present in 2.79 mol of NH₃.