Question

P4 (s) + 5O2 (g) P4O10 (g)
a) What mass of P4O10 forms when 2.7 g of O2 is used?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass

Answer 1

P_{4 (s)} + 5 O_{2 (g)} = P₄O_{10 (g)}

M (O₂) = 32 g/mol

M (P₄O₁₀) = 283.9 g/mol

n (O₂) = 2.7 / 32 = 0.08 mol

n (P₄O₁₀) = 1/5 x n (O₂) = 1/5 x 0.08 = 0.016 mol

m (P₄O₁₀) = 0.016 x 283.9 = 4.5 g