Answer to Question #148311 in Chemistry for Kristia Panares

Question

What mass of Na2S2O3 is needed to react with 0.12 g of Cl2?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass

Answer 1

Na₂S₂O₃ + Cl₂ + H₂O = S + Na₂SO₄ + 2 HCl

M (Cl₂) = 70.91 g/mol

M (Na₂S₂O₃) = 158.11 g/mol

n (Cl₂) = m/M = 0.12 / 70.91 = 0.002 mol

n (Na₂S₂O₃) = n (Cl₂) = 0.002 mol

m (Na₂S₂O₃) = n x M = 0.002 x 158.11 = 0.32 g