Solution:
A 2.0 M solution is 2.0 moles per liter.
Therefore, 0.5 L would contain:
(2.0 mol × 0.5 L) / 1.0 L = 1.0 mol
The molar mass of NaCl is 58.44 g/mol
So, one mole of NaCl weighs 58.44 g.
Hence, you would need:
1.0 mol × 58.44 g = 58.44 g.
Answer: 58.44 g of NaCl is needed.
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