Answer to Question #147780 in Chemistry for Avva

Question #147780
Calculate the standard entropy of formation of liquid ethanol at 25°C. [S0(Cgraphite) = 160.70J/K•mol, S0(O2) = 205.14 J/K•mol, S0(H2) = 130.68 J/K•mol, S0(C2H5OH) = 130.68 J/K•mol]
1
Expert's answer
2020-12-01T09:10:21-0500

The formal reaction of formation of liquid ethanol is:

2Cgraphite + 1/2O2 + 3H2 "\\rightarrow" C2H5OH.

Using Hess law, the standard entropy change of this reaction is:

"\u2206S = S^0_{ethanol} - 3S^0_{H_2} - 1\/2S^0_{O_2} - 2S^0_{graphite}"

"\u2206S = 130.68 - 3\u00b7130.68-0.5\u00b7205.14-2\u00b7160.70"

"\u2206S = -685.33" J/K·mol.


Answer: the standard entropy of formation of liquid ethanol is -685.33 J/K·mol.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS