Answer to Question #143674 in Chemistry for trinity lowery

Question

According to the following equation, how many moles of aluminum are needed to form 3.7 mol Al2O3?

4Al + O2

Answer 1

Solution:

The balanced chemical equation:

4Al + 3O₂ = 2Al₂O₃

According to the chemical equation:

n(Al)/4 = n(Al₂O₃)/2

n(Al)/2 = n(Al₂O₃)

n(Al) = 2 × n(Al₂O₃)

Hence,

n(Al) = 2 × 3.7 mol = 7.4 mol

Moles of Al = 7.4 moles

Answer: 7.4 moles of aluminum (Al) are needed to form 3.7 mol Al₂O₃