Question

WHAT IS THE MOLALITY (m) OF A 250 g OF SOLUTION THAT CONTAINS 7.3 GRAMS OF GLUCOSE C6H12O6? WHAT IS THE MOLECULAR WEIGHT OF SOLUTE?

Answer 1

M(C₆H₁₂O₆)=180.16 g/mol

n(C₆H₁₂O₆)=m/M = 7.3/180.16=0.04 mol

Cm(C₆H₁₂O₆)=0.04/0.25=0.16 m