Answer to Question #131290 in Chemistry for hannah

Question

Calculate the molarity of a 1,500ml solution which contains 200 grams aluminum chloride.

Answer 1

aluminum chloride = AlCl₃

Solution:

To get the molarity, need to divide the moles of solute by the litres of solution.

Molarity = moles of solute / litres of solution

1 mol of AlCl₃ has a mass of 133.34 g, so

Moles of AlCl₃ = 200 g AlCl₃ × (1 mol AlCl₃ / 133.34 g AlCl₃) = 1.4999 mol = 1.5 mol

Moles of AlCl₃ = 1.5 mol

Litres of solution = 1500 mL soln × (1 L soln / 1000 mL soln) = 1.5 L solution

Molarity of AlCl₃ = Moles of AlCl₃ / Litres of solution

Molarity of AlCl₃ = (1.5 mol AlCl₃) / (1.5 L soln) = 1 mol/L = 1 M

Answer: The molarity of AlCl₃ is 1 M.