Question #131289
Calculate the mass of ethyl alcohol which must be dissolved in 750 grams of water to make 0.5m solution.
1
Expert's answer
2020-09-02T10:09:25-0400

The molar concentration cc of ethyl alcohol solution is the ratio of the number of the moles of ethyl alcohol nn and the volume of the solution VV.

c=nVc =\frac{n}{V} .

The density of 0.5 M solution of ethanol at 20°C is 0.9939 g/mL. The molar mass MM of ethanol is 46.07 g/mol. Therefore:

c=meth/M(mw+meth)/dc = \frac{m_{eth}/M}{(m_w+m_{eth})/d}

0.5=meth/46.07(750+meth)/0.9939/10000.5 = \frac{m_{eth}/46.07}{(750+m_{eth})/0.9939/1000}

meth=17.8m_{eth} = 17.8 g.

Answer: 17.8 g of ethyl alcohol must be dissolved in 750 grams of water to make 0.5M solution at 20°C.


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