The molar concentration "c" of ethyl alcohol solution is the ratio of the number of the moles of ethyl alcohol "n" and the volume of the solution "V".
"c =\\frac{n}{V}" .
The density of 0.5 M solution of ethanol at 20°C is 0.9939 g/mL. The molar mass "M" of ethanol is 46.07 g/mol. Therefore:
"c = \\frac{m_{eth}\/M}{(m_w+m_{eth})\/d}"
"0.5 = \\frac{m_{eth}\/46.07}{(750+m_{eth})\/0.9939\/1000}"
"m_{eth} = 17.8" g.
Answer: 17.8 g of ethyl alcohol must be dissolved in 750 grams of water to make 0.5M solution at 20°C.
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