Question #131289

Calculate the mass of ethyl alcohol which must be dissolved in 750 grams of water to make 0.5m solution.

Expert's answer

The molar concentration cc of ethyl alcohol solution is the ratio of the number of the moles of ethyl alcohol nn and the volume of the solution VV.

c=nVc =\frac{n}{V} .

The density of 0.5 M solution of ethanol at 20°C is 0.9939 g/mL. The molar mass MM of ethanol is 46.07 g/mol. Therefore:

c=meth/M(mw+meth)/dc = \frac{m_{eth}/M}{(m_w+m_{eth})/d}

0.5=meth/46.07(750+meth)/0.9939/10000.5 = \frac{m_{eth}/46.07}{(750+m_{eth})/0.9939/1000}

meth=17.8m_{eth} = 17.8 g.

Answer: 17.8 g of ethyl alcohol must be dissolved in 750 grams of water to make 0.5M solution at 20°C.


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