Answer to Question #119758 in Chemistry for aljoc

Question

A bicycle tire has a pressure of 450. kPa at 20.0°C. Assuming the volume does not change, what is the new pressure at 35.0°C?

Answer 1

P₁ = 450. kPa

T₁ = 20.0°C = 293 K

P₂ = unknown

T₂ = 35.0°C = 308 K

V = constant

Solution:

Since the volume does not change, Gay-Lussac's law can be used.

Gay-Lussac's gas law can be expressed as: P₁/T₁ = P₂/T₂

To find the new pressure, solve the equation for P₂:

P₂ = (P₁ × T₂) / T₁

P₂ = (450. kPa × 308 K) / (293 K) = 473. kPa

P₂ = 473. kPa

Answer: 473 kPa is the new pressure at 35.0°C.