In the reaction
5Br−(aq)+BrO3-(aq)+6H+(aq)→3Br2(aq)+3H2O(l)
5 bromide ions react and produce 3 bromine molecules. The rate of reaction equals the rate of disappearance of a reagent divided by its stoichiometric coefficient:
.
The same relation is valid for the rate of formation of the bromine:
.
Using these two equations, we can easily calculate the rate of formation of Br2:
M/s.
Answer: the average rate of formation of Br2 during the same time interval is 6.36·10-5 M/s.
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