Let's write a balanced reaction equation:
C + 2S "\\rightarrow" CS2
As you can see, when 1 mol of C is consumed, 1 mol of CS2 is produced. Therefore, the number of the moles of carbon and that of carbon sulfide are equal:
"n(C) = n(CS_2)"
The molar mass of carbon is 12.01 g/mol. Let's calculate the number of the moles of carbon:
"n(C) = \\frac{m}{M} = \\frac{3.6}{12.01} = 0.30" mol.
Therefore, 0.30 mol of CS2 is formed.
Answer: If 3.6 grams of C react, 0.30 mol of CS₂ will be produced.
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