Question

If 3.6 grams of C react, how many moles of CS₂ will be produced?

Answer 1

Let's write a balanced reaction equation:

C + 2S $\rightarrow$ CS₂

As you can see, when 1 mol of C is consumed, 1 mol of CS₂ is produced. Therefore, the number of the moles of carbon and that of carbon sulfide are equal:

$n(C) = n(CS_2)$

The molar mass of carbon is 12.01 g/mol. Let's calculate the number of the moles of carbon:

$n(C) = \frac{m}{M} = \frac{3.6}{12.01} = 0.30$ mol.

Therefore, 0.30 mol of CS₂ is formed.

Answer: If 3.6 grams of C react, 0.30 mol of CS₂ will be produced.