Answer to Question #112962 in Chemistry for ximena

Question #112962
Determine the limiting reactant when 4.2 mol Fe(OH)3 reacts with 6.5 mol H2SO4 in the following reaction.

2 Fe(OH)3 + 3 H2SO4 --> Fe2(SO4)3 + 6 H2O
1
Expert's answer
2020-05-01T14:42:04-0400

2 Fe(OH)3 + 3 H2SO4 --> Fe2(SO4)3 + 6 H2O

Numbers of moles of each reactant must be devided by coefficients to find the limiting reactant:

n(Fe(OH)3) = 4.2 mol / 2 = 2.1 mol

n(H2SO4) = 6.5 mol / 3 = 2.17 mol

As number of moles of Fe(OH)3 is smaller (2.1 compared to 2.17), Fe(OH)3 is the limiting reactant.


Answer: Fe(OH)3 is the limiting reactant.

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