2 Fe(OH)3 + 3 H2SO4 --> Fe2(SO4)3 + 6 H2O
Numbers of moles of each reactant must be devided by coefficients to find the limiting reactant:
n(Fe(OH)3) = 4.2 mol / 2 = 2.1 mol
n(H2SO4) = 6.5 mol / 3 = 2.17 mol
As number of moles of Fe(OH)3 is smaller (2.1 compared to 2.17), Fe(OH)3 is the limiting reactant.
Answer: Fe(OH)3 is the limiting reactant.
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