Let's consider the electronic structure of the H2S molecule. Its central atom, S, has 6 electrons in its valence shell (you can see this from the Periodic Table, 3s23p4). Therefore, when two hydrogens share their two electrons with sulphur, sulphur atom has four electron pairs in the valence shell ( 2 pairs shared with hydrogens and 2 lone pairs). In VSEPR notation, this molecule is described as AX2E2, where A is the central atom (sulphur), X is the atom linked to the central atom (two hydrogens) and E is the non-bonding electron pair (2 pairs in this case). The electron-domain geometry of AX2E2 is bent (or angular). For this geometry, the angle is slightly lower than 109.5°, characteristic for tetrahedral geometry.
Answer: H2S:bent electron-domain geometry with 2 non bonding pairs on S will cause the bond angle to deviate from ideal 109,5 degrees angles.
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