Answer to Question #107432 in Chemistry for Ceci

Question

A balloon is filled with 2000 mL of air at a pressure of 2 atm. What is the volume of the balloon if the pressure is changed to 5 atm?

Answer 1

V₁ = 2000 mL =2 L;

P₁ = 2 atm;

V₂ = unknown;

P₂ = 5 atm.

Solution:

Let's apply Boyle's law (the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant).

For comparing the same substance under two different sets of conditions, the law can be expressed as:

P₁V₁ = P₂V₂

Then,

V₂ = P₁V₁ / P₂ = (2 atm * 2 L) / (5 atm) = 0.8 L = 800 mL;

V₂ = 800 mL.

Answer: 800 mL is the volume of the balloon if the pressure is changed to 5 atm.