Answer to Question #107376 in Chemistry for Hhu

Question

5. A 931 g block of ice has just melted completely into a liquid. If 4753.2 J of heat are added to the water, what is the final temperature?

Answer 1

Solution:

Suppose that a block of ice is already melted and is a liquid (water) at 0°C.

Therefore, m(H₂O) = m(block of ice) = 931 g.

In this case, the following process is realized:

- liquid (water) at 0^∘C --> liquid (water) at a final temperature (T_f).

Mathematically, the heat added to heat water from a liquid at 0°C to a liquid at a final temperature is expressed as follows:

q = c(H₂O) * m * ΔT = c(H₂O) * m * (T_f − 0);

where is the specific heat of water = c(H₂O) = 4.184 J g^−1∘C⁻¹

You will have:

q = (4.184 J g^−1∘C⁻¹) * (931 g) * (T_f − 0)^∘C = 4753.2 J;

4753.2 = 3895.304 * (T_f − 0);

1.22 = T_f − 0;

T_f = 1.22^∘C

Answer: 1.22^∘C is the final temperature