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(a) 0.100 mol dm–3 NaOH
(b) 0.100 mol dm–3 Ca(OH)2
(c) 0.0500 mol dm–3 KOH
Thank you.
Please classify the following as either homogeneous or heterogeneous mixtures
I) paint
ii) alchol
iii) concrete
iv) milk
v) sugar
vi) soil
vii) cement
viii) milkshake
ix) a bottle of soft drink
x) salt
xi) seawater
I just want to confirm that I got the concept of mixtures very well. Thank you so much, sir.
1. Protein broken down in the stomach by enzyme pepsin.
2. More bubbles appear when s concentrated solution of hydrochloric acid is added to magnesium strip than when a dilute solution of the acid is added.
3. Raw potatoes are cut into thin slices for cooking.
4. Blowing air on campfire to help it going.
5. Grains of sugar dissolves quickly in water.
6. Smaller pieces of charcoal are used to grill food.
7. Meat is stored in a refrigerator to last longer.
8. Acid rain erodes marble faster.
9. Protease is used to tenderize meat.
10. Leaving a glass of Milk on the table causes it to spoil easily.
Thank you!
What is the Factor Affecting Reaction Rate of the following scenario/situation:
1. Protein broken down in the stomach by enzyme pepsin.
2. More bubbles appear when s concentrated solution of hydrochloric acid is added to magnesium strip than when a dilute solution of the acid is added.
3. Raw potatoes are cut into thin slices for cooking.
4. Blowing air on campfire to help it going.
5. Grains of sugar dissolves quickly in water.
6. Smaller pieces of charcoal are used to grill food.
7. Meat is stored in a refrigerator to last longer.
8. Acid rain erodes marble faster.
9. Protease is used to tenderize meat.
10. Leaving a glass of Milk on the table causes it to spoil easily.
An ideal gas undergoes a mechanically reversible process (constant pressure, constant temperature and adiabatic process. The gas entering a T1=650K and P1=10bar decreases its temperature at constant pressure where V2=2.91x10- 3 m3. Then, it went to isothermal process to decrease its pressure. Finally, the gas returns to its initial state. Take
Cp=7
2
Cu2S, Cu and Cu2O solid phases for Cu-O-S system at 727oC and 1 atm total pressure. You may use
the standard free energy change values (G
0
, Kcal) at 727oC for the following reactions: [R = 1.987
Cal/mole/K] i) 2Cu(s) +0.5O2(g) = Cu2O(s), G
0 = -22.7; ii) 2Cu(s) + 0.5S2(g) = Cu2S(s), G
0 = -24.05;
iii) S2(g) + 2O2(g) = 2SO2(g), G
0 = -138.64
roasted with (20+RN*)% excess air. Copper in the roasted product is as Cu2S and all the iron is
converted to Fe2O3. Assuming that the gangue does not contain any Cu, Fe and S, Calculate for 1
ton of concentrate i) amount of minerals and gangue ii) volume of air supplied for roasting at STP.
iii) Volume and composition of the evolved gas (flue) after roasting [atomic weight of Cu=64, Fe=
56, S=32, O=16, N=14]
