Question #93948
A balloon blown up has volume of 500ml at 5°C balloon is distended to 7/8th of its maximum capacity 1) will it burst at 30°C. 2) calculate the minimum temperature above. Which it will burst
1
Expert's answer
2019-09-09T06:49:01-0400

Volume of balloon=500ml=500 ml

Volume currently filled up(V1)=78×500=437.5ml(V_1)=\frac{7}{8}\times 500=437.5 ml

Current temperature(T1)=5°C=273+5=278K(T_1)=5 \degree C=273+5=278 K

1)1) T2=30°C=273+30=303KT_2=30\degree C=273+30=303 K

Using equation,V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}

437.5278=V2303\frac{437.5}{278}=\frac{V_2}{303}

V2=437.5×303278=476.84mlV_2=\frac{437.5 \times 303}{278}=476.84ml

So it is less than 500 ml and the balloon will not burst.

2)2) The balloon will burst when the volume exceeds 500 ml,so the limiting case is V2=500mlV_2=500 ml

V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}

437.5278=500T2\frac{437.5}{278}=\frac{500}{T_2}

T2=500×278437.5=317.71KT_2=\frac{500 \times 278}{437.5}=317.71 K

So,the balloon will burst at temperature greater than 317.71K or 317.71273=44.71°C317.71 K \space or \space 317.71-273=44.71 \degree C


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