Question #80142

A solution containing Na2CO3 and NaOH requires 300ml of 0.1 N HCl using phenolpthalein as an indicator. Methyl orange is then added to the above titrated solution when a further 25ml 0f 0.2N HCl is required. the amount of NaOH present in soultion is?
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Expert's answer

2018-08-27T04:25:01-0400

Answer on Question #80142 - Chemistry - Physical Chemistry

Question:

A solution containing Na2CO3 and NaOH requires 300ml of 0.1 N HCl using phenolphthalein as an indicator. Methyl orange is then added to the above titrated solution when a further 25ml of 0.2N HCl is required. the amount of NaOH present in solution is?

Solution:

Na2CO3+2HCl=NaCl2+H2O\mathrm{Na_2CO_3 + 2HCl = NaCl_2 + H_2O}

n(HCl)=cV=0.10.3=0.03mol;\mathrm{n(HCl)} = \mathrm{c}^{*}\mathrm{V} = 0.1^{*}0.3 = 0.03\mathrm{mol};

n(HCl)=n(NaOH)=0.03mol;\mathrm{n(HCl)} = \mathrm{n(NaOH)} = 0.03\mathrm{mol};

n(HCl)2=cV=0.20.025=0.005mol\mathrm{n(HCl)_2 = c^*V = 0.2^*0.025 = 0.005mol}

n(HCl)total=0.035mol;\mathrm{n(HCl)_{total}} = 0.035\mathrm{mol};

w(NaOH)=0.03/0.065=0.4615=46.15%\mathrm{w(NaOH)} = 0.03 / 0.065 = 0.4615 = 46.15\% .

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