Answer to Question #7466 in Physical Chemistry for Crystal

Question

128 grams of oxygen reacted. After the combustion of an unknown hydrocarbon, the total pressure of a 18.91-L container is 7.3347 atm at 22.7 degrees celsius. What is the hydrocarbon?

Answer 1

PV=nRT
n1=PV/RT
n=7.3347*101.3*18.91/8.31*295.7=5.718
moles
n2=128/32=4
CO2 is gas at this condition
CxHy + (x+y/4)O2=xCO2
+y/2H2O
as we see,coefficient near O2 (x+y/4) must be biger that near CO2
x.Coefficients are proportional to the amounts (n2 must be > than n1),so this
task can't be solved.