Question #6960
conjunction with 2.1 g of iron with sulfur separated 3.77 kJ. calculate the heat of formation of iron sulfide
Expert's answer
Fe + S=FeS
nFe =2.1/55.85=0.03760
0.03760 moles-------3.77 kj
1
moles-----------------x kj
x=100.27 kJ
nFe =2.1/55.85=0.03760
0.03760 moles-------3.77 kj
1
moles-----------------x kj
x=100.27 kJ
