Answer to Question #222970 in Physical Chemistry for Caren

Question

A radioactive decay involves the emission of n aplha particles and m beta particles. Given that the decay process involves the reaction 714N → n24He +m0-1β + n1n2X. Given that the values of n1,n2 , n and m are calculated theoretically such that n1 - m(d/dy (1/y)) = 7 where y=-1.

A. n2 = 14-n

B. n1 = 7

C. n2 =14-3n

D. m=2n

E. n1 = 7-2m + n

Answer 1

1/2 = e –(λ*T1/2)

C. n2 =14-3n