Answer to Question #221679 in Physical Chemistry for Preshy

Question

A vessel containing an unknown volume of Argon in cm³at 300°F and 101kpa was inverted and placed in cold Ethanol. As the gas contracted , the pressure was quadrapled while the temperature was reduced by one _third.

What is the final volume of the gas in dm³

Answer 1

V₁=?

T₁=300ºF   

P₁ = 101kPa

 

V₂ =?

T₂=100°F

P2=404kPa

 PV = nRT

T₁ = 300 ⁰F = (5/9 x (300 - 32)) + 273 = 422 K;

T₂ = 300/3 = 100 ⁰F = 311 K

P₁ = 101 kPa = 101000 Pa

P₂ = 101 kPa x 4 = 404 kPa = 404000 Pa

P₁V₁ / T₁ = P₂V₂ / T₂

101000 x V₁ / 422 = 404000 x V₂ / 311

= 512.969882 m/s