An engine containing 2 kg air as working substance is initially at 1 atm and 27 degree celcius.
The system undergoes isochoric process to a point where pressure of the system is 2
atm. At this point heat is transferred to the air untill the volume doubles. Calulate
the total workdone and the amount of heat transferred to the air.
W= (nRT/V)ΔV
T = 300K
= 2*8.31*300/(0.5 π 0.12) )*(0.01 π 0.12) J = 279 J
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