Answer to Question #215630 in Physical Chemistry for shruti

Question

Using the following data, calculate the amount of energy by which benzene is more

stable as compared to one Kekule structure:

∆fH*=(methane, g) = −84.85 kJ/mol

∆fH*=(ethane, g) = −94.85 kJ/mol

∆fH*=(ethylene, g) = −65.35 kJ/mol

∆fH*=(benzene, g) = −98.45 kJ/mol

C (graphite) → C (g); ∆H* = 714.39 kJ/mol

H2(g) → 2H(g) ∆H* = 435.89 kJ/mol

(here '*' denotes degree sign)

Answer 1

Amount of energy by which benzene is more stable=$-150kJ$