Answer to Question #167942 in Physical Chemistry for Satyajay Mandal

Question

If 22.7 moles of aqua regia (a compound made from 22.7 moles of HNO₃ and 68. 1 moles of HCl or 90.8 moles of H, 68.1 moles of Cl, 22.7 moles of N and 68.1 moles of O) is neutralised by 22.7 moles of the mentioned mixture of NaOH and KOH (composed of 22.7 moles of Na, 68.1 moles of K, 90.8 moles of O and 90.8 moles of H) then how many moles each of Na, N, O, H, K, Cl are produced as the final product?

Answer 1

No change in total amount of each element occurs in a reaction. The number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. This means that the products will include:

Na 22.7 moles

N 22.7 moles

O 68.1 + 90.8 = 158.9 moles

H 90.8 + 90.8 = 181.6 moles

K 68.1 moles

Cl 68.1 moles